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(C) In $O_2$ ($16$ electrons),the molecular orbital configuration is $(\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\sigma 2p_z)^2 (\pi

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$O_2$

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(C) In $O_2$ ($16$ electrons),the molecular orbital configuration is $(\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\sigma 2p_z)^2 (\pi 2p_x)^2 (\pi 2p_y)^2 (\pi^* 2p_x)^1 (\pi^* 2p_y)^1$. $sp$ mixing is generally significant for molecules with $14$ or fewer electrons (like $B_2, C_2, N_2$). For $O_2$,the energy of $2s$ and $2p$ orbitals is sufficiently different that $sp$ mixing is negligible. Even if $sp$ mixing were considered,the magnetic nature of $O_2$ (paramagnetic due to two unpaired electrons in $\pi^*$ orbitals) remains unchanged because the filling order of the higher energy orbitals is not affected by $sp$ mixing in this case.

Which of the following molecules would have the same magnetic nature regardless of whether $sp$ mixing is operative or not?

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